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Exam Code: H13-527_V5.0
Exam Name: HCIP-Cloud Computing V5.0Certification
Version: V16.75
Q & A: 400 Questions and Answers
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NEW QUESTION: 1
A. Option A
B. Option D
C. Option B
D. Option C
Answer: C
Explanation:
First use the Import-Module ADDSDeployment command in PowerShell-it includes the cmdlets needed to add new domain controllers. Then run Install-ADDSDomainController along with the required arguments. Quick Tip: DCPromo.exe has been deprecated but can still be used along with an answer file, and ADPrep.exe runs automatically when needed (but can be run with elevated rights for more control).
NEW QUESTION: 2
Which of the following describes the benefits of Cognos Application Firewall (CAF)?
A. It protects the application by monitoring all HTTP requests sent through the Web server to ensure the gateway is receiving valid requests.
B. It allowsCognos 8 BI to run over the Internet.
C. It encrypts all input requests for validation before they are sent to the dispatcher.
D. It monitors and validates all input requests to prevent parameter manipulation, SQL injection, and buffer overflow.
Answer: D
NEW QUESTION: 3
You have a DNS server named Server1 that runs Windows Server 2016. Server1 has two Active Directory- integrated zones named contoso.com and adatum.com.
All client computers run Windows 10.
Server1 recently experienced millions of erroneous DNS queries causing a denial of service.
You need to reduce the likelihood that a similar attack will cause a denial of service. The solution must ensure that Server1 continuous to resolve names for clients.
What should you do?
A. Enable Response Rate Limiting (RRL) on Server1
B. Configure DNS policies on Server1
C. Sign both adatum.com and contoso.com zones
D. Implement DNS-based Authentication of Named Entities (DANE)
Answer: A
Explanation:
Explanation/Reference:
References:
https://blogs.technet.microsoft.com/teamdhcp/2015/08/28/response-rate-limiting-in-windows-dns-server/
NEW QUESTION: 4
Sara, a security administrator, is noticing a slowdown in the wireless network response. Sara launches a
wireless sniffer and sees a large number of ARP packets being sent to the AP. Which of the following type
of attacks is underway?
A. IV attack
B. Blue jacking
C. Interference
D. Packet sniffing
Answer: A
Explanation:
Section: Threats and Vulnerabilities
Explanation/Reference:
Explanation:
In this question, it's likely that someone it trying to crack the wireless network security.
An initialization vector is a random number used in combination with a secret key as a means to encrypt
data. This number is sometimes referred to as a nonce, or "number occurring once," as an encryption
program uses it only once per session.
An initialization vector is used to avoid repetition during the data encryption process, making it impossible
for hackers who use dictionary attack to decrypt the exchanged encrypted message by discovering a
pattern. This is known as an IV attack.
A particular binary sequence may be repeated more than once in a message, and the more it appears, the
more the encryption method is discoverable. For example, if a one-letter word exists in a message, it may
be either "a" or "I" but it can't be "e" because the word "e" is non-sensical in English, while "a" has a
meaning and "I" has a meaning. Repeating the words and letters makes it possible for software to apply a
dictionary and discover the binary sequence corresponding to each letter.
Using an initialization vector changes the binary sequence corresponding to each letter, enabling the letter
"a" to be represented by a particular sequence in the first instance, and then represented by a completely
different binary sequence in the second instance.
WEP (Wireless Equivalent Privacy) is vulnerable to an IV attack. Because RC4 is a stream cipher, the
same traffic key must never be used twice. The purpose of an IV, which is transmitted as plain text, is to
prevent any repetition, but a 24-bit IV is not long enough to ensure this on a busy network. The way the IV
was used also opened WEP to a related key attack. For a 24-bit IV, there is a 50% probability the same IV
will repeat after 5000 packets.
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