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NEW QUESTION: 1
Data Quality Services（DQS）ナレッジベースを管理します。
DQSが同一のタグ間に同義語関係を作成するようにする必要があります。
何を作るべきですか？
A. term-based relations
B. new domain
C. linked domain
D. new knowledge base
Answer: A
Explanation:
Explanation
If a term-based relation transformation causes two values to be identical, then DQS will create a synonym relationship between them (in knowledge discovery), a correction relationship between them (in data correction), or an exact match (in matching).
References:
https://docs.microsoft.com/en-us/sql/data-quality-services/create-term-based-relations

NEW QUESTION: 2

A. IP services
B. enterprise access
C. IP base
D. LAN base
Answer: A

NEW QUESTION: 3
During an installation of View Connection Server, the Install HTML Access option setting is not being displayed in the installer.
What is the probable cause?
A. IPv6 is selected as Internet Protocol (IP).
B. Configure Windows Firewall automatically option is selected.
C. FIPS mode is disabled.
D. IPv4 is selected as Internet Protocol (IP).
Answer: A

NEW QUESTION: 4
View the Exhibit.
Select the SQL statement that corresponds to the record definition.

A. SELECT A.COURSE,A.STUDENT_ID,A.SESSION_NBR,STUDENT_NAME,CUSTOMER_ID,C.DESC R,A.ENROLL_DT,A.ENROLL_STATUSFROM PS_PSU_STU_ENROLL A, PS_PSU_STUDENT_TBL B, PS_PSU_CUST_TBL BWHERE A.STUDENT_ID = STUDENT_IDAND CUSTOMER_ID = CUSTOMER_ID
B. SELECT A.COURSE,A.STUDENT_ID,A.SESSION_NBR,B.STUDENT_NAME,B.CUSTOMER_ID,DESC R,A.ENROLL_DT,A.ENROLL_STATUSFROM PS_PSU_STU_ENROLL A, PS_PSU_STUDENT_TBL B, PS_PSU_CUST_TBL CWHERE A.STUDENT_ID = B.STUDENT_IDAND B.CUSTOMER_ID = CUSTOMER_ID
C. SELECT A.COURSE SELECT A.COURSE,A.STUDENT_ID,A.SESSION_NBR,B.STUDENT_NAME,B.CUSTOMER_ID,C.DESC R,A.ENROLL_STATUS,A.ENROLL_DATEFROM PS_PSU_STU_ENROLL A, PS_PSU_STUDENT_TBL B, PS_PSU_CUST_TBL CWHERE A.STUDENT_ID = B.STUDENT_IDAND B.CUSTOMER_ID = C.CUSTOMER_ID
D. SELECT COURSE,SESSION_NBR,B.STUDENT_NAME,B.CUSTOMER_ID,C.DESCR,ENROLL_DT ,ENROLL_STATUSFROM PS_PSU_STU_ENROLL A, PS_PSU_STUDENT_TBL B, PS_PSU_CUST_TBL CWHERE STUDENT_ID = B.STUDENT_IDAND B.CUSTOMER_ID=
E. CUSTOMER_ID
Answer: B,E