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NEW QUESTION: 1
The of a storage device are redundant, including controller modules, management modules, BBU modules, interface modules, power modules, and fan modules. Component redundancy ensures system reliability.
A. TRUE
B. FALSE
Answer: A

NEW QUESTION: 2
In the world of keystroke dynamics, what represents the amount of time you hold down in a particular key?
A. Systems time
B. Dwell time
C. Dynamic time
D. Flight time
Answer: B
Explanation:
Keystroke dynamics looks at the way a person types at a keyboard. Specifically, keyboard dynamics measures two distinct variables: "dwell time" which is the amount of time you hold down a particular key and "flight time" which is the amount of time it takes a person to switch between keys. Keyboard dynamics systems can measure one's keyboard input up to 1000 times per second.

NEW QUESTION: 3
アジャイルの原則を使用して、新しい支払いシステムが構築されています。顧客のデモンストレーション中に、製品の所有者がモジュール機能の変更を要求します。スコープドキュメントとユーザーストーンを調べると、最初のプロジェクトドキュメントに含まれているものに変更が加えられていないことが明らかになります。
プロジェクトマネージャーは次に何をすべきですか？
A. 変更管理システムを介してリクエストを送信します。
B. 次のスプリントに変更を含めます
C. 変更を含めるためにプロジェクトを再ベースライン化します
D. 変更に対応するために利害関係者に予算の増額を要求する
Answer: A

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
o. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
D. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Incorrect:
Not A: Should not use GROUP BY on CustomerName.
Not B: We must not display all order. Need a Where o.Rnk = 1
Not C: Should order by the number of orders, not the amount of the orders. ORDER BY COUN T (OrderAmount), not ORDER BY OrderAmount, must be used.