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NEW QUESTION: 1
展示を参照してください。ルータR1はOSPFルータIDとして何を使用しますか？

A. 172.16.15.10
B. 192.168.0.1
C. 10.10.10.20
D. 10.10.1.10
Answer: A
Explanation:
OSPF uses the following criteria to select the router ID:
1. Manual configuration of the router ID (via the "router-id x.x.x.x" command under OSPF router configuration mode).
2. Highest IP address on a loopback interface.
3. Highest IP address on a non-loopback and active (no shutdown) interface.

NEW QUESTION: 2
The first DROPoperation is performed on PRODUCTStable using this command:
DROP TABLE products PURGE;
Then a FLASHBACKoperation is performed using this command:
FLASHBACK TABLE products TO BEFORE DROP;
Which is true about the result of the FLASHBACKcommand?
A. It recovers only the table structure.
B. It recovers the table structure, data, and the indexes.
C. It recovers the table structure and data but not the related indexes.
D. It is not possible to recover the table structure, data, or the related indexes.
Answer: D
Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_9003.htm

NEW QUESTION: 3
DRAG DROP
Drag and drop the BGP components from the left onto the correct descriptions on the right.

Answer:
Explanation:
BGP speaker: device that is running BGP
+ Prefix = Value that is advertised with the network keyword.
eBGP Peer = neighbor that located outside of administrative domain of the local device.
BGP Peer = neighbor device that shares the same AS number as the local device.
Autonomous system number = Value that identifies an administrative domain

NEW QUESTION: 4
An administrator is reviewing the following output:
VIP(141.128.58.149:80:UP:WEIGHTEDRR): Hits(38200495, 18/sec) Mbps(1.02)
Pers(OFF) Err(0)
Pkt(186/sec, 610 bytes) actSvc(4) DefPol(NONE) override(0)
Conn: Clt(253, 1/sec, OE[252\]) Svr(3)
S(141.128.49.40:80:UP) Hits(9443063, 4/sec, P[2602342, 0/sec\]) ATr(5)
Mbps(0.23)BWlmt(100 kbits) RspTime(112.58 ms)
Other: Pkt(36/sec, 712 bytes) Wt(10000) RHits(31555) Conn: CSvr(42, 0/sec) MCSvr(20) OE(16) RP(11) SQ(0)
How much traffic is being passed through the public IP address based on the output displayed above?
A. 0.23 Mbps
B. 100 kbits
C. 1.02 Mbps
D. 112.58 ms
Answer: C