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NEW QUESTION: 1
What are two characteristics of Frame Relay point-to-point subinterfaces? (Choose two.)
A. They are ideal for full-mesh topologies.
B. They require a unique subnet within a routing domain.
C. They require the use of NBMA options when using OSPF.
D. They create split-horizon issues.
E. They emulate leased lines.
Answer: B,E
Explanation:
http://www.ciscopress.com/articles/article.asp?p=170741&seqNum=5
Configuring Frame Relay Subinterfaces
On partially meshed Frame Relay networks, the problem of split horizon can be overcome by using Frame Relay subinterfaces. Frame Relay provides a mechanism to allow a physical interface to be partitioned into multiple virtual interfaces. In a similar way, using subinterfaces allows a partially meshed network to be divided into a number of smaller, fully meshed point-to-point networks. Generally, each point-to-point subnetwork is assigned a unique network address. This allows packets received on one physical interface to be sent out from the same physical interface, albeit forwarded on VCs in different subinterfaces.
There are two types of subinterfaces supported by Cisco routers: point-to-point and multipoint subinterfaces.

NEW QUESTION: 2
Which of the following would be an inappropriate procedure for the custodian of the medical record to perform prior to taking a medical record from a health care facility to court?
A. Document in the file folder the total number of pages in the record.
B. Prepare an itemized list of sheets contained in the medical record.
C. Remove any information that might prove detrimental to the hospital or physician.
D. Number each page of the record in ink.
Answer: C

NEW QUESTION: 3

class Sum extends RecursiveAction { //line n1
static final int THRESHOLD_SIZE = 3;
int stIndex, lstIndex;
int [ ] data;
public Sum (int [ ]data, int start, int end) {
this.data = data;
this stIndex = start;
this. lstIndex = end;
}
protected void compute ( ) {
int sum = 0;
if (lstIndex - stIndex <= THRESHOLD_SIZE) {
for (int i = stIndex; i < lstIndex; i++) {
sum += data [i];
}
System.out.println(sum);
} else {
new Sum (data, stIndex + THRESHOLD_SIZE, lstIndex).fork( );
new Sum (data, stIndex,
Math.min (lstIndex, stIndex + THRESHOLD_SIZE)
).compute ();
}
}
}
and the code fragment:
ForkJoinPool fjPool = new ForkJoinPool ( ); int data [ ] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} fjPool.invoke (new Sum (data, 0, data.length));

A. Option D
B. Option A
C. Option B
D. Option C
Answer: D