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Exam Code: 1Z0-1114-25
Exam Name: Oracle Redwood Application 2025 Developer AssociateCertification
Version: V16.75
Q & A: 400 Questions and Answers
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NEW QUESTION: 1
You plan to create an Azure Cosmos DB account that uses the SQL API. The account will contain data added by a web application. The web application will send data daily.
You need to recommend a notification solution that meets the following requirements:
Sends email notification when data is received from IoT devices.
Minimizes compute cost.
What should you include in the recommendation?
A. Deploy a function app that is configured to use the Consumption plan and a SendGrid binding.
B. Deploy an Azure logic app that has a SendGrid connector configured to use an Azure Cosmos DB action.
C. Deploy an Azure logic app that has the Azure Cosmos DB connector configured to use a SendGrid action.
D. Deploy a function app that is configured to use the Consumption plan and an Azure Event Hubs binding.
Answer: A
NEW QUESTION: 2
A. Option B
B. Option C
C. Option D
D. Option A
Answer: D
NEW QUESTION: 3
A. CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
C. CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
I. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
J. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
Answer: I
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp
NEW QUESTION: 4
A. Option A
B. Option C
C. Option D
D. Option B
Answer: D
|
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