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The Open Group OG0-093 Free Exam, OG0-093 Cert Exam | Latest OG0-093 Braindumps Pdf - Sugakumaster

OG0-093

Exam Code: OG0-093

Exam Name: TOGAF 9 Combined Part 1 and Part 2Certification

Version: V16.75

Q & A: 400 Questions and Answers

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NEW QUESTION: 1
Which one of the following queries selects the customer whose order has the highest total price?
A. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createquery(customer.class)
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
B. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.cteateQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
C. CriteriaBuilder cb = ...
Criteria Query <Customer> cq = cb.create Query (Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
D. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = sq.from(Order.class);
sq. select (ci: . max ( subo . get (Order_ . Total Price) ) ) ;
cq.where(sq.all(o.gei(Order_.totalPrice)));
Answer: A

NEW QUESTION: 2
You created a new database using the "create database" statement without specifying the "ENABLE PLUGGABLE" clause.
What are two effects of not using the "ENABLE PLUGGABLE database" clause?
A. The database is treated as a PDB and must be plugged into an existing multitenant container database (CDB).
B. The database is created as a non-CDB but will become a CDB whenever the first PDB is plugged in.
C. The database is created as a non-CDB but can be plugged into an existing CDB.
D. The database is created as a non-CDB and can never be plugged into a CDB.
E. The database is created as a non-CDB and can never contain a PDB.
Answer: C,E
Explanation:
Explanation
A (not B,not E): The CREATE DATABASE ... ENABLE PLUGGABLE DATABASE SQL statement creates a new CDB. If you do not specify the ENABLE PLUGGABLE DATABASE clause, then the newly created database is a non-CDB and can never contain PDBs.
D: You can create a PDB by plugging in a Non-CDB as a PDB.
The following graphic depicts the options for creating a PDB:

Incorrect:
Not E: For the duration of its existence, a database is either a CDB or a non-CDB. You cannot transform a non-CDB into a CDB or vice versa. You must define a database as a CDB at creation, and then create PDBs within this CDB.

NEW QUESTION: 3
AWSでの統合請求の利点は次のうちどれですか?
A. アカウントごとに複数の請求書
B. 共有アクセス許可
C. タグ付けの必要性を排除します
D. ボリューム価格の資格
Answer: D
Explanation:
If you have multiple standalone accounts, your charges might decrease if you add the accounts to an organization. AWS combines usage from all accounts in the organization to qualify you for volume pricing discounts.

NEW QUESTION: 4
Which of these metrics cannot help detect a DDoS?
Choose the correct answer:
A. ELB SurgeQueueLength
B. EMR EMRspersecond
C. CloudFront Requests
D. EC2 CPUUtilization
Answer: B
Explanation:
EMR EMRspersecond doesn't exist.

OG0-093 Related Exams
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