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NEW QUESTION: 1
Which two statements about a wireless access point configured with the guest-mode command are true?
(Choose two.)
A. If one device on a network is configured is guest mode, clients can use the guest mode SSID to connect to any device on the same network.
B. It allows clients configured without SSID to associate.
C. It can support more than one guest-mode SSID.
D. It supports associations by clients that perform passive scans.
E. It allows associated clients to transmit packets using its SSID.
Answer: B,C
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
B. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
C. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
D. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
Answer: B
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network 10.10.10.0/24 is 20 + 50 = 70.

Before a router can be considered a feasible successor, it must pass the feasibility condition rule.
In short, the feasibility condition says that if we learn about a prefix from a neighbor, the advertised
distance from that neighbor to the destination must be lower than our feasible distance to that
same destination.
Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the
feasibility condition.

NEW QUESTION: 3
Given:

What is the result?
A. Capital A
B. simaple A default
C. simaple A
D. Compilation fails.
E. simaple A default Capital A
Answer: E
Explanation:
Here we have to use two ternary operators combined. SO first we can use to check first
condition which is x > 10, as follows;
x>10?">": (when condition false) Now we have to use another to check if x<10 as follows;
x<10?V:"=" We can combine these two by putting last ternary statement in the false
position of first ternary statement as follows;
x>10?">":x<10?'<':"="
https;//docs.oraclexom/javase/tutorial/java/nutsandbolts/if.html