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NEW QUESTION: 1
Betrachten Sie den folgenden Pseudocode:
1 Beginnen Sie
2 Lesezeit
3 Wenn die Zeit <12 ist, dann
4 Drucken (Uhrzeit, "am")
5 Endif
6 Wenn Zeit> 12 Dann
7 Drucken (Uhrzeit 12, "pm")
8 Endif
9 Wenn Zeit = 12 Dann
1 0 Drucken (Uhrzeit, "Mittag")
1 1 Endif
1 2 Ende
Wie viele Testfälle sind erforderlich, um eine 100-prozentige Entscheidungsabdeckung zu erreichen?
A. 0
B. 1
C. 2
D. 3
Answer: D
Explanation:
Erläuterung:
Die drei Entscheidungen sind aufeinanderfolgend und die Bedingungen schließen sich gegenseitig aus (wenn eine wahr ist, müssen die anderen falsch sein). Ein Testfall, bei dem die erste Entscheidung wahr ist, macht die zweite und dritte Entscheidung falsch und so weiter.
Testfall 1 (sagen wir Zeit = 6) würde also den Pfad Wahr, Falsch, Falsch ausüben, Testfall 2 (sagen wir Zeit = 15) würde den Pfad Falsch, Wahr, Falsch ausüben. Testfall 3 müsste Zeit sein
= 12. Diese Kombination erreicht eine 100-prozentige Entscheidungsabdeckung, da jede Entscheidung durch ihre wahren und ihre falschen Ergebnisse ausgeführt wurde.

NEW QUESTION: 2



A. Option A
B. Option C
C. Option B
D. Option D
Answer: A
Explanation:
Only router can break up broadcast domains but in this exhibit no router is used so there is only 1 broadcast domain. For your information, there are 7 collision domains in this exhibit (6 collision domains between hubs & switches + 1 collision between the two switches).

NEW QUESTION: 3
During the EAP process and specifically related to the client authentication session, which encrypted key is sent from the RADIUS server to the access point?
A. shared-secret key
B. WPA key
C. encryption key
D. session key
Answer: D
Explanation: