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NEW QUESTION: 1
What are two limitations of the Atomic IP Advanced Engine? (Choose two.)
A. It is unable to inspect a packet's length fields for bad information.
B. It is unable to detect IP address anomalies, including IP spoofing
C. It is unable to fire high-severity alerts for known vulnerabilities.
D. It is unable to detect Layer 4 attacks if the packets were fragmented by IPv6.
E. It has limited ability to check the fragmentation header.
Answer: D,E
Explanation:
The Atomic IP Advanced engine contains the following restrictions:
Cannot detect the Layer 4 field of the packets if the packets are fragmented so that the Layer 4 identifier does not appear in the first packet.
Cannot detect Layer 4 attacks in flows with packets that are fragmented by IPv6 because there is no fragment reassembly.
Cannot detect attacks with tunneled flows.
Limited checks are provided for the fragmentation header.
There is no support for IPv6 on the management (command and control) interface. With ASA 8.2(1), the ASA 5500 AIP SSM support IPv6 features.
If there are illegal duplicate headers, a signature fires, but the individual headers cannot be separately inspected.
Anomaly detection does not support IPv6 traffic; only IPv4 traffic is directed to the anomaly detection processor.
Rate limiting and blocking are not supported for IPv6 traffic. If a signature is configured with a block or rate limit event action and is triggered by IPv6 traffic, an alert is generated but the action is not carried out.
Reference: http://www.cisco.com/c/en/us/td/docs/security/ips/71/configuration/guide/ime/imeguide71/ime_signature_engines.pdf

NEW QUESTION: 2
Given a limited amount of storage, a technician wants to maximize capacity for multiple hosts and utilization efficiency. Which of the following would BEST achieve this?
A. Thin provisioning
B. Compression
C. LUN load balancing
D. Encryption
Answer: A

NEW QUESTION: 3
What is the highest normal form of the relation(s) shown in the exhibit?

A. Second normal form
B. No normal form
C. First normal form
D. Third normal form
Answer: D

NEW QUESTION: 4

Select and Place:

Answer:
Explanation: