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NEW QUESTION: 1
A customer is experiencing z/OS performance problems on their z13 while the system is taking a memory
dump. Which chargeable z Systems feature could provide relief for this problem?
A. Simultaneous Multithreading
B. Flash Express
C. Single Instruction Multiple Data
D. zEnterprise Data Compression
Answer: A
Explanation:
Explanation/Reference:
Typical simultaneous multithreading (SMT) implementations allow workloads from different control
programs to use a compute core concurrently, but with variable core capacity gains and thread execution
slowdowns. The new IBM z13 platform implements SMT differently. At any point in time, a single control
program manages the entire core, giving each workload more repeatable core capacity for processing.
References: http://www.redbooks.ibm.com/abstracts/redp5144.html?Open

NEW QUESTION: 2
Which two are tasks that can be performed using EPM Automate? (Choose two.)
A. import premapped data
B. export journals
C. export balances
D. set period status
Answer: A,C

NEW QUESTION: 3
A developer is writing an application with three java Persistence API entities: order, customer, and Address. There is a many-to-one relationship between order and customer, and a one to-many relationship between customer and Address.
Which two Criteria queries will return the orders of all customers who have an address whose value specified by the String parameter postalcode? (Choose two)
A. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq- from (Order . class ) ,
Join<order, Address> address = order . join (Order_. customer) -join (Customer_.addresses);
cq.where <cb.equal (address.get(Address_.postalCode) , postalCode) ) ;
cq.selec:(order).distinct(true);
// query execution code here
. . .
B. String postalCode = . . .
Criteria Builder cb = . . .
CriteriaQuery<order> cq = cb.createQuery (Order.class);
Root <order> order = cq.from(order.class);
Join <order, Customer> customer = order.join(Order_.customer);
Root <Order> order = cq.from (Order.class);
Join <customer, Address> address = customer join (Order_.customer)
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
. . .
C. String postalCode = . . .
Criteria Builder cb = . . .
Root <Order> order = cq.from (Order.class);
order.join (order_. customer).join(Customer_.addresses);
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
D. String postalCode = ...
CritetiaBuilder cb = ...
Root<order> order = cq - from (Order . class) ,
Join<order, Address> address = order.join(Customer_.addresses);
cq.where(ct>.equal(address.get(Address_.postalCode), postalCode));
cq-select(order).distinct(true);
// query execution code here
. . .
Answer: A,D