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NEW QUESTION: 1
Why will a switch never learn a broadcast address?
A. Broadcasts only use network layer addressing.
B. Broadcast frames are never sent to switches.
C. A broadcast address will never be the source address of a frame.
D. Broadcast addresses use an incorrect format for the switching table.
E. A broadcast frame is never forwarded by a switch.
Answer: C
Explanation:
Switches dynamically learn MAC addresses based on the source MAC addresses that it sees, and since a broadcast is
never the source, it will never learn the broadcast address.

NEW QUESTION: 2
Which of the following are the specific rules for equipment layout?
A. Ensure easy equipment maintenance.
B. Reserve appropriate distances between equipment.
C. Lay out equipment in the inside-out sequence.
D. Efficiently utilize equipment room space.
Answer: A,D

NEW QUESTION: 3
You develop a Microsoft SQL Server 2012 database.
You need to create and call a stored procedure that meets the following requirements:
Accepts a single input parameter for CustomerID.
Returns a single integer to the calling application.
Which Transact-SQL statement or statements should you use? (Each correct answer presents part of the
solution. Choose all that apply.)
A. EXECUTE dbo.GetCustomerRatIng 1745
B. CREATE PROCEDURE dbo.GetCustomerRating @CustomerID INT, @CustomerRating INT OUTPUT AS
SET NOCOUNT ON
SELECT @Result = CustomerOrders/CustomerValue
FROM Customers WHERE CustomerID = @CustomeriD
RETURN @Result
GO
C. DECLARE @customerRatingBycustomer INT DECLARE @Result INT EXECUTE @Result = dbo.GetCustomerRating 1745 , @CustomerRatingSyCustomer
D. CREATE PROCEDURE dbo.GetCustomerRating @CustomerID INT AS DECLARE @Result INT SET NOCOUNT ON SELECT @Result = CustomerOrders/CustomerVaLue FROM Customers WHERE Customer= = @CustomerID RETURNS @Result
E. DECLARE @CustomerRatIngByCustcmer INT
EXECUTE dbo.GetCustomerRating @CustomerID = 1745,
@CustomerRating = @CustomerRatingByCustomer OUTPUT
F. CREATE PROCEDURE dbo.GetCustomerRating @Customer INT, @CustomerRatIng INT OUTPUT AS SET NOCOUNT ON SELECT @CustomerRating = CustomerOrders/CustomerValue FROM Customers WHERE CustomerID = @CustomerID RETURN GO
Answer: C,D

NEW QUESTION: 4
Given:

What is the result?
A. Welcome Log 2:1
B. Hello Log 1:0
C. Hello Log 2:1
D. Welcome Log 1:0
Answer: A