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Exam Code: HPE0-J68
Exam Name: HPE Storage SolutionsCertification
Version: V16.75
Q & A: 400 Questions and Answers
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NEW QUESTION: 1
The process for performing variance analysis may vary, depending on:
A. working relationships among various stakeholders and team members.
B. application area, the standard used, and the industry,
C. scenario building, technology forecasting, and forecast by analogy.
D. work to be completed next.
Answer: B
NEW QUESTION: 2
Refer to the graphic, three Layer 2 switches enabled with STP are connected to the same hub.
The configuration of bridge IDs is as follows while all other configurations use default values.
Which of the following statements is false?
A. LSW1 is selected as the root bridge by comparing the bridge IDs.
B. G0/0/2on LSW1 is blocked
C. G0/0/1 on LSW3 is for AP Port and is blocked.
D. The two interfaces on LSW1 are designated ports and are in the forwarding state.
Answer: D
NEW QUESTION: 3
You are evaluating the performance of a database environment.
You must avoid unnecessary locks and ensure that lost updates do not occur.
You need to choose the transaction isolation level for each data scenario.
Which isolation level should you use for each scenario? To answer, drag the appropriate isolation levels to the correct scenarios. Each isolation may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Explanation
Box 1: Readcommitted
Read Committed: A transaction T1 executing under this isolation level can only access committed data.
Pros: Good compromise between concurrency and consistency.
Cons: Locking and blocking. The data can change when accessed multiple times within the same transaction.
Box 2: Read Uncommitted
Read Uncommitted (aka dirty read): A transaction T1 executing under this isolation level can access data changed by concurrent transaction(s).
Pros: No read locks needed to read data (i.e. no reader/writer blocking). Note, T1 still takes transaction duration locks for any data modified.
Cons: Data is not guaranteed to be transactionally consistent.
Box 3: Serializable
Serializable: A transaction T1 executing under this isolation level provides the highest data consistency including elimination of phantoms but at the cost of reduced concurrency. It prevents phantoms by taking a range lock or table level lock if range lock can't be acquired (i.e. no index on the predicate column) for the duration of the transaction.
Pros: Full data consistency including phantom protection.
Cons: Locking and blocking. The S locks are held for the duration of the transaction that can lower the concurrency.
References:
https://blogs.msdn.microsoft.com/sqlcat/2011/02/20/concurrency-series-basics-of-transaction-isolation-levels/
NEW QUESTION: 4
Refer to the exhibit.
C-router is to be used as a "router-on-a-stick" to route between the VLANs. All the interfaces have been properly configured and IP routing is operational. The hosts in the VLANs have been configured with the appropriate default gateway. What is true about this configuration?
A. These commands need to be added to the configuration: C-router(config)# router eigrp 123 C-router(config-router)# network 172.19.0.0
B. These commands need to be added to the configuration: C-router(config)# router rip C-router(config-router)# network 172.19.0.0
C. These commands need to be added to the configuration: C-router(config)# router ospf 1 C-router(config-router)# network 172.19.0.0 0.0.3.255 area 0
D. No further routing configuration is required.
Answer: D
Explanation:
Since all the same router (C-router) is the default gateway for all three VLANs, all traffic destined to a different VLA will be sent to the C-router. The C-router will have knowledge of all three networks since they will appear as directly connected in the routing table. Since the C-router already knows how to get to all three networks, no routing protocols need to be configured.
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