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Exam Code: 1z0-1047-24
Exam Name: Oracle Absence Management Cloud 2024 Implementation ProfessionalCertification
Version: V16.75
Q & A: 400 Questions and Answers
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NEW QUESTION: 1
A. 2003:dead:beef:4dad:23:46:bb:101
B. 2002:c0a8:101::42
C. 2001:3452:4952:2837::
D. ::192:168:0:1
E. 2000::
F. ::
Answer: A,B,D,F
Explanation:
http://www.intermapper.com/ipv6validator http://www.ripe.net/lir-services/new-lir/ipv6_reference_card.pdf
NEW QUESTION: 2
Which two are true about record store listeners? (Choose two.)
A. Listeners are notified if a record store is deleted.
B. When a record store is closed, listeners are removed.
C. A record store can have more than one registered listener.
D. To listen for all events, three listeners must be registered.
E. A record store can have only one registered listener.
Answer: B,C
NEW QUESTION: 3
What are the two characteristics of Multitenancy?
A. It requires users to change position to access appropriate data.
B. It allows up-to-date overview of customer service effectiveness.
C. It allows users to navigate through multi-interactions.
D. It allows a Call Center agent to support multiple clients at once.
E. Agents cannot manually assume appropriate role based on inbound work items.
Answer: D,E
Explanation:
Reference: http://docs.oracle.com/cd/E14004_01/books/PDF/CommSrvAdm.pdf (page 188, and 190)
NEW QUESTION: 4
Given the code fragment:
Which code fragment, when inserted at line n1, enables the code to print the could of string elements whose length is greater than three?
A. listVal. Stream().peek [x -> x.length{} > 3} count ().Get()
B. listVal. Stream(). Filter(x, length {) > 3}. count ()
C. listVal. Stream().map {x -> x.length {) >3}. count ()
D. listVal. Stream().filter(x-> x.length{) > 3.} .mapToint{x -> x).count()
Answer: B
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