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NEW QUESTION: 1

A. Option C
B. Option A
C. Option B
D. Option D
Answer: C
Explanation:
References:
https://www.ibm.com/support/knowledgecenter/SSAW57_8.5.5/com.ibm.websphere.nd.doc
/ae/cprf_rpa.html

NEW QUESTION: 2
One of the theories behind NetProfiler Services is:
A. None of the above.
B. Applications are large and complex and often traverse different groups within a single organization.
Without the concept of a service in NetProfiler, it would not be possible to monitor the traffic from a single application since each group would have no purchase their own NetProfiler to monitor their individual aspect of the application.
C. When monitoring an application, it is often necessary to think of that application as a service instead of an application. By utilizing NetProfiler Services, you are able to take your application and easily convert it to a service. This conversion allows you to treat the application differently so it can be more effectively monitored.
D. Many organizations do not know all the aspects of a given application or service they provide, which makes it difficult to fully map that service and monitor it from end to end. NetProfiler has visibility into many different areas and can often see connections used by different parts of a service that may be unknown to different administrators. This visibility allows NetProfiler to identify all the different components of a service and provide detailed visibility and monitoring into that service's performance.
Answer: D

NEW QUESTION: 3
Which three fields can be included in a pcap filter? (Choose three)
A. Ingress interface
B. Rule number
C. Source IP
D. Destination IP
E. Egress interface
Answer: A,C,D

NEW QUESTION: 4
次のデータを含むSalesという名前のテーブルがあります。

テーブルにクエリを実行して、1日の平均売上高を返す必要があります。出力は次の結果を生成する必要があります。

どのようにクエリを完了する必要がありますか？答えるには、適切な値を正しいターゲットにドラッグします。各値は、1回使用することも、複数回使用することも、まったく使用しないこともできます。コンテンツを表示するには、分割バーをペイン間でドラッグするか、スクロールする必要がある場合があります。
注：正しい選択はそれぞれ1ポイントの価値があります。

Answer:
Explanation:

Explanation

Box 1: SELECT
Box 2: GROUP BY
Example:
When used with a GROUP BY clause, each aggregate function produces a single value covering each group, instead of a single value covering the whole table. The following example produces summary values for each sales territory in the AdventureWorks2012 database. The summary lists the average bonus received by the sales people in each territory, and the sum of year-to-date sales for each territory.
SELECT TerritoryID, AVG(Bonus)as 'Average bonus', SUM(SalesYTD) as 'YTD sales' FROM Sales.SalesPerson GROUP BY TerritoryID;