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1Z0-770 Zertifikatsdemo, Oracle 1Z0-770 Fragen Beantworten & 1Z0-770 Testfagen - Sugakumaster

1Z0-770

Exam Code: 1Z0-770

Exam Name: Oracle APEX Developer ProfessionalCertification

Version: V16.75

Q & A: 400 Questions and Answers

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About Oracle 1Z0-770 Exam

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1Z0-770 Studienmaterialien: Oracle APEX Developer Professional - 1Z0-770 Torrent Prüfung & 1Z0-770 wirkliche Prüfung

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NEW QUESTION: 1
Joe, a user, in a coffee shop is checking his email over a wireless network. An attacker records the temporary credentials being passed to Joe's browser. The attacker later uses the credentials to impersonate Joe and creates
SPAM messages. Which of the following attacks allows for this impersonation?
A. Header manipulation
B. XML injection
C. Session hijacking
D. Directory traversal
Answer: C
Explanation:
In computer science, session hijacking, sometimes also known as cookie hijacking is the exploitation of a valid computer session-sometimes also called a session key-to gain unauthorized access to information or services in a computer system. In particular, it is used to refer to the theft of a magic cookie used to authenticate a user to a remote server. It has particular relevance to web developers, as the HTTP cookies used to maintain a session on many w eb sites can be easily stolen by an attacker using an intermediary computer or with access to the saved cookies on the victim's computer.
Incorrect Answers:
A. When a web user takes advantage of a weakness with SQL by entering values that they should not, it is known as a
SQL injection attack. Similarly, when the user enters values that query XML (known as XPath) with values that take advantage of exploits, it is known as an XML injection attack. XPath works in a similar manner to SQL, except that it does not have the same levels of access control, and taking advantage of weaknesses within can return entire documents. The best way to prevent XML injection attacks is to filter the user's input and sanitize it to make certain that it does not cause XPath to return more data than it should. This is not what is described in this question. This answer is therefore incorrect.
B. Directory traversal is a form of HTTP exploit in which a hacker uses the software on a Web server to access data in a directory other than the server's root directory. If the attempt is successful, the hacker can view restricted files or even execute commands on the server.
Although some educated guesswork is involved in finding paths to restricted files on a Web server, a skilled hacker can easily carry out this type of attack on an inadequately protected server by searching through the directory tree. The risk of such attacks can be minimized by careful Web server programming, the installation of software updates and patches, filtering of input from browsers, and the use of vulnerability scanners. This is not what is described in this question. This answer is therefore incorrect.
C. A header manipulation attack uses other methods (hijacking, cross-site forgery, and so forth) to change values in
HTTP headers and falsify access. When used with XSRF, the attacker can even change a user's cookie. Internet
Explorer 8 and above include InPrivate Filtering to help prevent some of this. By default, your browser sends information to sites as they need it-think of requesting a map from a site; it needs to know your location in order to give directions. With InPrivate Filtering, you can configure the browser not to share information that can be captured and manipulated. This is not what is described in this question. This answer is therefore incorrect.
References:
http://en.wikipedia.org/wiki/Session_hijacking
http://searchsecurity.techtarget.com/definition/directory-traversal
Dulaney, Emmett and Chuck Eastton, CompTIA Security+ Study Guide, 6th Edition, Sybex, Indianapolis, 2014, pp. 337,
340

NEW QUESTION: 2
-- Exhibit -user@qfabric> show fabric administration inventory Item Identifier Connection Configuration Node group
LC1-SNG Connected Configured LC1 P2399-C Connected NW-NG-0 Connected Configured LC0 P1992-C Connected RSNG Connected Configured LC2 P4098-C Connected LC3 P3716-C Connected
Interconnect device IC-0 IC-P4847-C Connected Configured P4847-C/RE0 Connected
IC-1 IC-P4881-C Connected Configured P4881-C/RE0 Connected Fabric manager FM-0 Connected Configured
Fabric control FC-0 Connected Configured FC-1 Connected Configured
Diagnostic routing engine DRE-0 Connected Configured
user@qfabric> show Ethernet-switching table
Ethernet-switching table: 44 entries, 10 learned VLAN MAC address Type Age Interfaces VLAN100 00:05:33:64:c0:a5 Static - LC0:xe-0/0/32.0 VLAN100 00:05:33:64:c6:a9 Static - LC1:xe-0/0/32.0 VLAN100 0e:fc:00:01:02:09 Static - LC1:xe-0/0/32.0
......
qfabric-admin@FC-0> show route fabric table bgp.bridgevpn.0
bgp.bridgevpn.0: 27 destinations, 54 routes (27 active, 0 holddown, 0 hidden) Restart Complete
+ = Active Route, - = Last Active, * = Both
65534:1:14.0:5:33:64:c0:a5/144 *[BGP/170] 1w4d 01:31:37, localpref 100 AS path: I, validation-state: unverified > to 128.0.128.4 via dcfabric.0, Push 1663, Push 8, Push 49(top)
[BGP/170] 1w4d 01:31:37, localpref 100, from 128.0.128.8
AS path: I, validation-state: unverified
> to 128.0.128.4 via dcfabric.0, Push 1663, Push 8, Push 49(top) 65534:1:14.0:5:33:64:c6:a9/144
*[BGP/170] 1w4d 01:36:37, localpref 100
AS path: I, validation-state: unverified
> to 128.0.130.18 via dcfabric.0, Push 1683, Push 7, Push 49(top)
[BGP/170] 1w4d 01:36:37, localpref 100, from 128.0.128.8
AS path: I, validation-state: unverified
> to 128.0.130.18 via dcfabric.0, Push 1683, Push 7, Push 49(top) 65534:1:14.e:fc:0:1:2:9/144
*[BGP/170] 1w4d 01:36:37, localpref 100
AS path: I, validation-state: unverified
> to 128.0.130.18 via dcfabric.0, Push 1683, Push 7, Push 49(top)
[BGP/170] 1w4d 01:36:37, localpref 100, from 128.0.128.8
AS path: I, validation-state: unverified
> to 128.0.130.18 via dcfabric.0, Push 1683, Push 7, Push 49(top) 65534:1:14.e:fc:0:1:2:14/144
*[BGP/170] 1w4d 01:31:37, localpref 100
AS path: I, validation-state: unverified
> to 128.0.128.4 via dcfabric.0, Push 1663, Push 8, Push 49(top)
[BGP/170] 1w4d 01:31:37, localpref 100, from 128.0.128.8
AS path: I, validation-state: unverified
> to 128.0.128.4 via dcfabric.0, Push 1663, Push 8, Push 49(top) ...
qfabric-admin@FC-0> show route advertising-protocol bgp 128.0.130.18 bridge-route-macaddress 00:05:33:64:c0:a5 fabric table bgp.bridgevpn.0
bgp.bridgevpn.0: 26 destinations, 52 routes (26 active, 0 holddown, 0 hidden)
Restart Complete
Prefix Nexthop MED Lclpref AS path
-- Exhibit -
Click the Exhibit button.
Host A on the Node device LC1 is not able to connect to Host B on the Node device LC0.The MAC address of Host A is 00:05:33:64:c6:a9. The MAC address of Host B is 00:05:33:64:c0:a5.
Referring to the exhibit, what is causing this problem?
A. The fabric route table on the fabric control Routing Engine does not have MAC address of Host A.
B. The fabric manager Routing Engine has not learned the MAC addresses from both Node devices.
C. Hosts A and B are on different VLANs.
D. The fabric control Routing Engine is not advertising the MAC address of Host B to the Node device LC1.
Answer: D

NEW QUESTION: 3
The default Composer Perspective in GVP 8.1.2 includes views with the Project Explorer, Palette, the Block Properties and several editors.
A. False
B. True
Answer: B

NEW QUESTION: 4

Which statement is correct based on this configuration?
A. 00:0c:29:29:38:da is the virtual MAC address assigned to the secondary IP address (10.0.1.254) of the port1 interface.
B. Access to the network is blocked for the devices with the MAC address 00:0c:29:29:38:da and the IP address 10.0.1.254.
C. The IP address 10.0.1.254 is reserves for the device with the MAC address 00:0c:29:29:38:da.
D. The MAC address 00:0c:29:29:38:da belongs to the port1 interface.
Answer: C

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